0=12x^2+8x-32

Solution for 0=12x^2+8x-32 equation:

0=12x^2+8x-32

We move all terms to the left:

0-(12x^2+8x-32)=0

We add all the numbers together, and all the variables

-(12x^2+8x-32)=0

We get rid of parentheses

-12x^2-8x+32=0

a = -12; b = -8; c = +32;
Δ = b2-4ac
Δ = -82-4·(-12)·32
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-40}{2*-12}=\frac{-32}{-24}
=1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+40}{2*-12}=\frac{48}{-24}
=-2
$